Oregon chain

[dimanager]

My brother has an older Oregon chain. It has a 25 stamped on the raker and a 50 on the drive tag. I can not find anything on the Oregon site with this number on the tag. Any body know about the ID of this chain, guage or anything else. It looks like a ripping chain but I'm not sure. It is 3/8 pitch.

Thanks, Sam

 

[cuttinscott]

Its Windsor

If it has 50 on the driver it is a Windsor chain using the oregon tooth

Scott

 

[dimanager]

Thanks Scott. Then I believe that the 50 means the guage is .050. Is this correct?

Sam

 

[Cut4fun]

Maybe this chain cross ref guide might help you out.
http://www.brownandwiser.com/oregon_chain_cross_ref.html

 

[cuttinscott]

Thanks Scott. Then I believe that the 50 means the guage is .050. Is this correct?

Sam

Gague... Yes 50 is for .050" as would be the case with 58 or 63 as well. the cutter style is APLG windsor = LP oregon tooth, APL = LG oregon tooth, APLX = JG Oregon skip tooth.

Scott

 

[NBailey]

My brother has an older Oregon chain. It has a 25 stamped on the raker and a 50 on the drive tag. I can not find anything on the Oregon site with this number on the tag. Any body know about the ID of this chain, guage or anything else. It looks like a ripping chain but I'm not sure. It is 3/8 pitch.

Thanks, Sam

If it is really old (pre 90s), it is .404 x .050 gauge (50CP, 50AL, etc). The windsor chain usually says 50A, not just 50.

 

[SawTroll]

Maybe this chain cross ref guide might help you out.
http://www.brownandwiser.com/oregon_chain_cross_ref.html

That one is quite good, but a bit dated, and at least a couple of mistakes in the Husky column.....

21BP=H25 (not 27)
73LP=H42 (not 41)

 

[cuttinscott]

If it is really old (pre 90s), it is .404 x .050 gauge (50CP, 50AL, etc). The windsor chain usually says 50A, not just 50.

Yep Nick is right i forgot all about 50LP and the like I never sold .404" in .050" always .063" so I stocked and remembered 52 and 59 series chain.

Scott

 

[Grande Dog]

Measure three rivets center to center and divide by two. That will settle the pitch question.