You'd just have to figure the volume of each log. A cord is 128 cubic feet. The formula for volume is pi(about 3.14159) x radius squared x length ( do all measurements in feet). For example, if you had a 12" round log that was 20 ft long, it would work out to just under 63 cubic feet. So, if you wanted 10 full cords, you'd need a bit over 20 logs. 7 full cords would be a bit over 14. Hope this helps!
I am planning to cut down some trees this weekend. Most are 8 inch or larger and at least twenty foot before you get to the branches. Just trying to figure how many trees i need to get 7 to 10 cords.
You'd just have to figure the volume of each log. A cord is 128 cubic feet. The formula for volume is pi(about 3.14159) x radius squared x length ( do all measurements in feet). For example, if you had a 12" round log that was 20 ft long, it would work out to just under 63 cubic feet. So, if you wanted 10 full cords, you'd need a bit over 20 logs. 7 full cords would be a bit over 14. Hope this helps!
The formula for volume is pi(about 3.14159) x radius squared x length ( do all measurements in feet).
Not exactly correct. The radius is the measurement from the middle of the circle to the outside. THe diameter is the measurement from outside to outside. Logs are measured by diameter.
This is a grapple load that was sold as 7 Cord....
The guy actually said he threw on some extra for me.
Looks like a lot of wood on the truck
When dumped on the ground it sure looks like less
I guess I wont know till It's all split.
Oh yeah, I paid $85 a cord or $595
I'm hoping it's two years worth for me.
This is a grapple load that was sold as 7 Cord....
The guy actually said he threw on some extra for me.
Looks like a lot of wood on the truck
When dumped on the ground it sure looks like less
I guess I wont know till It's all split.
Oh yeah, I paid $85 a cord or $595
I'm hoping it's two years worth for me.
Stihl051 is correct on how to find volume. Pi x r^2 x length
Yes logs are usually measured in diameter but in order to calculate volume, you must use the radius (half the diameter).
However, it is true that a cord (the way it's written) takes into effect airspace in a tightly stacked pile of wood.
How about this then: Pi/4 * D^2
This is a grapple load that was sold as 7 Cord....
The guy actually said he threw on some extra for me.
Looks like a lot of wood on the truck
When dumped on the ground it sure looks like less
I guess I wont know till It's all split.
Oh yeah, I paid $85 a cord or $595
I'm hoping it's two years worth for me.
This is a grapple load that was sold as 7 Cord....
The guy actually said he threw on some extra for me.
Looks like a lot of wood on the truck
When dumped on the ground it sure looks like less
I guess I wont know till It's all split.
Oh yeah, I paid $85 a cord or $595
I'm hoping it's two years worth for me.
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