torque vs chainspeed

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Think of a polar bear that eats a fish ,and another polar bear eats a seal ,which bear is going to have need more tourque and which one is going to have more horsepower when he expels gas .

Torque is irrelevant. This thread has taught me that torque is not needed, as magically you can get chain speed to overcome any load and that if you want to increase the load you can apply and maintain the same chain speed all you need is more power. And somehow we are producing more power at the same rpm without increasing torque, even though the equation for power has been shown to be torque x rpm = power.

I also learned that an optimum blend of piss and tears will allow you to cut cookies with a 390xp. Don't attempt to cut anything bigger than a 10x10 cant, though, because evidently tears don't like bigger wood.
 
Torque is irrelevant. This thread has taught me that torque is not needed.
Close. Torque= HP x 5252/RPM
Torque isn't irrelevant, in the case of an engine it isn't an independent variable. You don't run your car on a power dyno, then switch over to a torque dyno. The only things that matter are what power is produced and at what rpm. "Torque" is simply a linear mathematical formula based on the above variables and a fixed constant (5252). "Torque" is increased by either increasing the power, or producing the power at a lower RPM.
 
Close. Torque= HP x 5252/RPM
Torque isn't irrelevant, in the case of an engine it isn't an independent variable. You don't run your car on a power dyno, then switch over to a torque dyno. The only things that matter are what power is produced and at what rpm. "Torque" is simply a linear mathematical formula based on the above variables and a fixed constant (5252). "Torque" is increased by either increasing the power, or producing the power at a lower RPM.

No, torque is a measurable force. 1lb of force applied on a 1' lever = 1ft-lb. Horsepower is a calculation, torque (measured in ft-lbs) x rpm/5252= horsepower.

You have torque and horsepower in the wrong positions of your equation. They are not interchangeable.







I am partially wrong in this post and probably several more. I misread huskstihl's equation. I kept transposing rpm and 5252 in my brain and seeing it as torque=hp x rpm/5252.
 
Understeer is when you hit the wall with the front of the car, oversteer is when you hit the wall with the rear of the car.
Horsepower is how fast you hit the wall and torque is how far you take the wall with you.

All of this of course I have taught my wife in preparation for her driving test next Tuesday.
 
Understeer is when you hit the wall with the front of the car, oversteer is when you hit the wall with the rear of the car.
Horsepower is how fast you hit the wall and torque is how far you take the wall with you.

All of this of course I have taught my wife in preparation for her driving test next Tuesday.

How may horsepower does a sled dog have?
 
No, torque is a measurable force. 1lb of force applied on a 1' lever = 1ft-lb. Horsepower is a calculation, torque (measured in ft-lbs) x rpm/5252= horsepower.

You have torque and horsepower in the wrong positions of your equation. They are not interchangeable.
We have a linear equation with three variables and a constant. If you like to see power as a somewhat artificial product of torque and RPM, that's cool with me. I only have issues with some peoples concept that they are different, and that it is possible to have "more torque" without a change in the power at a given rpm
 
I had a fairly factual smart ass comment typed up. But I decided to let it go as humor is often hard to read, and I don't want to offend anyone. It seems you guy's are arguing a similar point from two different perspectives.
 
We have a linear equation with three variables and a constant. If you like to see power as a somewhat artificial product of torque and RPM, that's cool with me. I only have issues with some peoples concept that they are different, and that it is possible to have "more torque" without a change in the power at a given rpm

The variables positions are not interchangeable in the equation. The way you presented torque and horsepower is completely wrong.

http://en.wikipedia.org/wiki/Horsepower

You can have torque with 0 horsepower, but you cannot have horsepower with 0 torque.
 
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