Lakeside53
Stihl Wrenching
Belgian:
It's all "torque"
It's all "torque"
Belgian:
It's all "torque"
Screw fastening methods and proceedures differ greatly than a discussion of the internal combustion engine,in reference to torque.If taking the TQ-wrench idea out of the discussion helps prove your point, why do we seem to sweat more TQing the last say 1/8 of a turn then say the first 2 inches of a bolt?
The friction of a bolt is measuring the "Brake-horsepower" needed to TQ the bolt. Unless you have actualy ran the TQ on a few dozen "Torque to Yield " bolts, you would not understand the concept.
That doesn't have anything to do with what we are discussing. With your wrench you apply a torque to the bolt by a lever and a force. They rotate together with the same speed. Hence the torque applied on the bolt by the wrench is the same as the torque applied on the wrench by the bolt.
This is however not true for combustion engines since you have gearboxes, flywheels etc. There you you can't say anything about the torque applied by the piston on the crank shaft without complete info about the whole system.
An enormous force on the piston won't help you if you don't have rpm's. Small force on piston, high rpm and a gear box will do the same thing - > What we refer to as engine torque" is of less interest.
What matters is what comes out (hp) of your black box.
What is the definition of horsepower Peter? The definition as James Watt defined it?
Screw fastening methods and proceedures differ greatly than a discussion of the internal combustion engine,in reference to torque.
In dealing with a bolt an old hard and fast rule applies.Righty tighty,lefty loosey.Tight is tight,too tight is broke.
Right. I was taking a different approach to the discussion by considering the chain and then relating that to the saw engine. You're right that the sprocket is between the two, but I was trying to keep things simple, especially since the sprocket turns at the same RPM as the saw engine.Hp is a function of torque and engine speed, not chain speed - the size of the sprocket desides how they relate.
What really is important for cutting speed is chain speed, and the efficiency of the chain - but you need torque to keep the chain speed (and engine speed) up.....
Hp is a function of torque and engine speed, not chain speed - the size of the sprocket desides how those speeds relate, and how much torque you need to keep them up.
horsepower = (torque/time)
I can't argue a bit on the bolt theory.FWIW this little portion of physics plays a big part in what I get paid to do.Do the words Atlas Copco or FEC ring a bell?But in line with your bolt analogy, bolt TQ is the measurement of friction in an inclined plane (bolt threads) or "work" Torque to yield bolts measure the amount of friction change (work change) as the bolt stretches.
Come to think of it, you could have a monstrously torquey engine which runs at low RPM and therefore has low HP (like a diesel or a big V8), but gear it and sprocket it so that you have good cutter speed. So maybe torque IS all that matters... for the engine. You just have to convert the engine torque into a good balance of chain speed and force applied to the chain.
As I said:
Horsepower is a calculation of torque applied over time. Different formulae give different numbers.
The R part of RPM is irrelevant, the M part is what counts.
I can't argue a bit on the bolt theory.FWIW this little portion of physics plays a big part in what I get paid to do.Do the words Atlas Copco or FEC ring a bell?
The R and the M in rpm are both relevant. If the equation could be made simpler, it already would be.
It makes a big difference whether the engine turns 5K rpm or 10K rpm.
We'll deal with suckback after we've taken care of blowhard.I see everyone has carefully skirted the suckback controversy in this thread.
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